BBS: Inland Empire Archive
Date: 05-06-92 (23:44) Number: 149
From: DAVID BLISS Refer#: NONE
To: RICH GELDREICH Recvd: NO
Subj: projection Onto Plane. Conf: (2) Quik_Bas
> Lets say we have a four sided plane in 3-D space,
> like this:
> x----x
> ! !
> ! !
> ! !
> x----x
> Where each "x" has an X,Y, & Z coordinate. The
> plane could be in any
> position, not just what you see here.
> What I need: The coordinate of a point which is
> perpendicular to
> this plane when a line is drawn threw it to the center
> of the plane. If
> that isn't hard enough, the point must also be a
> certain distance from
> the plane too(such as 64 units or so). I can easily
This is so amazingly simple <g> (no offense of course!).
To find X,Y,Z of the point you said (assuming i understand
you), assuming the plane has four corners 1-4 and X,Y,Z of
these are X1-4 Y1-4 and Z1-4 and the point you need is X5
Y5 Z5,
X5=(x1-x2)+(x3-x4)/2 or whichever corners are on same line
Y5=(y1-y2)+(y3-y4)/2 " " " " " " "
Z5=(z1+z2+z3+z4)/4+64
What this does, is find the middle of the left side of the
plane, then the middle of the top side, and then give you a
point 64 units above that point. very simple geometry <bg>
but then i'm in very advanced math <g>
Hope this helps,
Dave
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