# 3-D

``` BBS: Inland Empire Archive
Date: 05-05-92 (21:23)             Number: 194
From: RON MCDERMOTT                Refer#: NONE
To: RICH GELDREICH                Recvd: NO
Subj: 3-D                            Conf: (2) Quik_Bas```
```Rich,

RG>What I need: The coordinate of a point which is perpendicular
RG>to this plane when a line is drawn threw it to the center of
RG>the plane.

Did you get my idea about using a dot product?  Combine that with
distance formula y=SQRT((x2-x1)^2+(y2-y1)^2) for the center point
and the off-plane point, and maybe setting the distance from any
two corners to the off-plane point equal, should give you three
equations in three unknowns (solvable, in theory <g>)!
---
* Origin: * Info-Center BBS * (914)567-1814  >>HST<< *  (1:272/26)
```

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