BBS: Inland Empire Archive Date: 01-03-93 (16:59) Number: 244 From: WES GARLAND Refer#: NONE To: JOHN GALLAS Recvd: NO Subj: calculations.. Conf: (2) Quik_Bas

Hi John! JG> I need some help with some calculations I have to do. JG> Lets say my spaceship has coordinates of 1550 and JG> 1438, and is facing 348 degrees (0 being straight JG> up), and is traveling 3 units per "update". Was that you asking about this stuff about a month? I wrote you a two-hour reply, explaining the practical applications of vector math.. I hope you got it.... JG> How do I calculate how much to add (or subtract) to the X and JG> Y? And would it still work if I wasn't using single JG> precision (no decimals)? First off all, in any calculation, keep the decimals until you absolutely can't... ANYHOW. The easiest way to do your calculation is this... ActualX = <your X coordinate> ActualY = <your Y coordinate> Set up a grid like this though: ^ |___ | /| | / | |/@ | <--+-----------> | V Your ship is at the plus. The diagonal line is R units long, which is the amount of space covered per update. @ is theta, the angle between the X-axis and your ship. So, using good ol' SOHCAHTOA, Sin @ = NewY/R Cos @ = NewX/R but remember, the computer uses radians for its trig calculations (I think... I KNOW earlier MSBasics did, and I don't imagine they've changed it...) So, the angle theta you plug in has to be converted from your coordinate system to this one, so you add ninety degrees (PI/2 rads) to it. Then you convert it to radians. Remember, theta is the angle between the line and the x axis. ======CONTINUTEDNEXTMESSAGE==== --- Maximus 2.01wb * Origin: Terminal Velocity Kingston *CANADA* (613)542-4613/6594, (1:249/128)

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